Question

the position of an object moving along x axis is given by x= a + bt^2 where a=8.5 m, b= 2.5m/sec^2 and t is measured in seconds . what is its velocity at t= 0 sec and t= 2.0 sec . what is the average velocity between t= 2.0 sec and t= 4.0 sec​

Answer 1

Explanation:

15 m s−1

Position is given as x=a+bt2=8.5+2.5t2

Position at t=2 s, x2=8.5+2.5(2)2=18.5 m

Position at t=4 s, x1=8.5+2.5(4)2=48.5 m

Displacement S=x2−x1=48.5−18.5=30 m

Time taken t=4−2=2 s

Average velocity Vavg=tS=230=15 m/s