The position of an object moving along x-axis is given by X = at bt2 , where a = 8.5m , b = 2.5 ms-1 and t is measured in seconds. What is its velocity at t = 0 and t = 2s ? What is the average velocity between t = 2s and t = 4s
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Answer:
15 m s −1
Explanation:
Position is given as x=a+bt
2
=8.5+2.5t
2
Position at t=2 s, x
2
=8.5+2.5(2)
2
=18.5 m
Position at t=4 s, x
1
=8.5+2.5(4)
2
=48.5 m
Displacement S=x
2
−x
1
=48.5−18.5=30 m
Time taken t=4−2=2 s
Average velocity V
avg
=
t
S
=
2
30
=15 m/s
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