Question

the position of an object moving along xaxis is given as x=a+bt2 where a=9m and b=4m/s2 .The mass of the object is 400 kg then the force is _________
plz solve with proper step by step please ​

Answer 1

Answer:

F=ma. We need to find a from given x

x=a+bt²

v =dx/dt =d( a+bt²)/dt =da/dt + d(bt²)/dt

v=0+2bt

v=2bt

a=dv/dt

a=d(2bt)/dt =2b. ( b=4)

a =2×4=8 m/s²

F=ma.

F= 400×8 =3200 N