The position of an object moving on a straight line is given by x=3-2t^2+3t^3where x is expressed in meter and t in second.
a) Derive the expressions for the velocity and acceleration of the object as a function of time.
b) Find the position of an object at t=0,t=2s and t=4s.
c)Find the Displacement of the object between t=2s and t=4s; between t=Os and t=4s.
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the expression of velocity is v= -4t+9t²
the expression of acceleration is a= -4+18t
at t=0 position =3
at t=2 position=19
at t=4 position=163
from t=2 to t=4 displacement =144
from t=0 to t=4 displacement = 160
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