The position of both, an electron and a helium atom is known within
1.0 nm. Further the momentum of the electron is known within 5.0 x 10⁻²⁶
kg ms⁻¹. The minimum uncertainty in the measurement of the momentum
of the helium atom is
(a) 50 kg ms⁻¹ (b) 80 kg ms⁻¹
(c) 8.0 × 10⁻²⁶ kg ms⁻¹ (d) 5.0 × 10⁻²⁶ kg ms⁻¹
Answers
Answered by
0
Answer:
d is the correct answer
Answered by
4
(d) 5.0 × 10⁻²⁶ kg
Explanation:
According to Heisenberg's Uncertainity principle, we know that:
∆x * ∆p ≥ h/4π
Position of both an electron & a helium atom = 1 nm
Momentum of an electron = 5 * 10^-26 kgm/s
When the postion of both the electron and helium atom is same, then the momentum of helium atom will be equal to momentum of an electron.
Momentum of Helium atom = 5 * 10^-26 kgm/s
Option D is the answer.
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