the position of centre of mass of a system consisting of two particles of masses M1 and M2 separated by a distance l apart from M1 will be
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Answer:
m1+m2/m1m2 is the distance of centre of mass from m1
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Answer:
Centre of Mass, Rcm = 
Explanation:
[Refer to the attached image to clearly understand the case]
Given;-
Masses of particles = m₁ and m₂
Length of separation of particles = L
Let R₁ be the position of m₁ and R₂ be the position of m₂.
Let us consider position of m₁ i.e. R₁ to be the origin i.e (0, 0).
Let Rcm denote the centre of mass.
Then, by formula, we know that;-
Rcm =
Rcm = 
Rcm = 
Hence, the position of centre of mass is
.
Hope it helps! ;-))
Attachments:

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