Question

the position of centre of mass of a system consisting of two particles of masses M1 and M2 separated by a distance l apart from M1 will be​

Answer 1

Answer:

m1+m2/m1m2 is the distance of centre of mass from m1

Answer 2

Answer:

Centre of Mass, Rcm = $\frac{m2 L}{m1 + m2}$

Explanation:

[Refer to the attached image to clearly understand the case]

Given;-

          Masses of particles = m₁ and m₂

Length of separation of particles = L

Let R₁ be the position of m₁ and R₂ be the position of m₂.

Let us consider position of m₁ i.e. R₁ to be the origin i.e (0, 0).

Let Rcm denote the centre of mass.

Then, by formula, we know that;-

                Rcm = $\frac{m1R1 + m2R2}{m1 + m2}$

                Rcm = $\frac{m1 (0) + m2(L)}{m1 + m2}$

                Rcm = $\frac{m2 L}{m1 + m2}$

Hence, the position of centre of mass is $\frac{m2L}{m1 + m2}$.

Hope it helps! ;-))