The position of o particle is given by x=t.t-2t find the distance and displacement at first 3sec .
Answers
Answered by
0
Answer:
It's too simple...
x=t^2-2t...
Differentiating w.r.t time...
V=2t-2...
Particle change its direction after velocity becomes zero...
Displacement =final position - initial position
=(3)^2-2(3)
=3m
Velocity becomes zero at V=0
2t-2=0
t=1 second
Distance traveled before velocity becomes zero or particle changes its direction = (1)^2-2(1)
=-1 i.e. 1(as displacement in negative direction but distance traveled is positive)
After t=1 second
Particle changes its direction and move in positive direction to 3m from origin... That is from - 1 to 3
=4m
So distance traveled = 1+4=5m...
Answered by an IIT JEE ASPIRANT...
Similar questions