Physics, asked by mk123321, 1 year ago

The position of o particle is given by x=t.t-2t find the distance and displacement at first 3sec .







Answers

Answered by Anonymous
0

Answer:

It's too simple...

x=t^2-2t...

Differentiating w.r.t time...

V=2t-2...

Particle change its direction after velocity becomes zero...

Displacement =final position - initial position

=(3)^2-2(3)

=3m

Velocity becomes zero at V=0

2t-2=0

t=1 second

Distance traveled before velocity becomes zero or particle changes its direction = (1)^2-2(1)

=-1 i.e. 1(as displacement in negative direction but distance traveled is positive)

After t=1 second

Particle changes its direction and move in positive direction to 3m from origin... That is from - 1 to 3

=4m

So distance traveled = 1+4=5m...

Answered by an IIT JEE ASPIRANT...

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