the position of particle moving along x axis is given by x=10t-2t^2.then the time t at which it will momently come to rest is
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diffrentiate x with respect to t..which is dx/dt=d(10t)/dt-d(2t^2)/dt
dx/dt=10-4t
since the particle is at rest thus velocity (dx/dt)is zero..
therefore 0=10-4t
t=5/2
if any doubts feel free too ask..
hope it helps.
dx/dt=10-4t
since the particle is at rest thus velocity (dx/dt)is zero..
therefore 0=10-4t
t=5/2
if any doubts feel free too ask..
hope it helps.
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