Question

the position of reflection of the point (4,1) about the line y=x-1 is​

Answer 1

Answer:

open this image you will get your answer

Answer 2

Answer:

hii dear please mark on

Step-by-step explanation:

Solution : Let Q(n,k) be the image of the point P (4,1) to the line k -n +1 =0 . Then PQ is perpendicular to k -n +1 =0 <br> ` (k-1)/(n-4) xx 1= -1` <br> k +n =4 +1=5 <br> Also , mid-point of PQ i.e,` ((4+n)/2 , (k+1)/2)` lies on k-n+1=0 <br> `( k -1)/(n-4) xx 1=-1` <br> k +n=4+1 =5 <br> Also, mid-point of PQ , i.e` ((4+n)/2 , (k+1)/2)` lies on <br> k-n +1 =0 <br> `(k+1)/2, (4+n)/2 +1 =0` <br> k -n-1=0 <br> on solving Eqs. (i) and (ii) we get the required point (2,3)