the position of stone dropped from rest from a cliff is given by x=5t^2.what is the velocity of stone at t=3s ?
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Explanation:
Position is given by x=5t²
So we need velocity
for velocity we will need to differentiate x with respect to 't'
i.e x=5*2t=10t
at t=3sec
10{3}=30m/s
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