Question

The position of the partical moving along a straight line is given by x=2-5t +t³ find the acceleration of the partical at t=2s​

Answer 1

it's your ans-

x = position

v = velocity

a = acceleration

x = 2 - 5t +  t^3

by differenciation,

v = -5 + 3t^2

by differenciation,

a = 6 t

now,

t = 2 sec

a = 6 t

= 6 * 2

= 12 m/sec

therefore, the acceleration is 12 m/sec.

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