Question

the position of the particle given by r=3ti+2tsquare j+5k​

Answer 1

Answer:

Given:

r

=3t

i

^

+2t

2

j

^

+5

k

^

Velocity,

v

=

dt

d

r

=

dt

d(3t

i

^

+2t

2

j

^

+5

k

^

)

=3

i

^

+4t

j

^

ms

−1

Let θ be the angle in which the direction of

v

makes with the x-axis.

At t=1sec:

Then tanθ =

v

x

v

y

=

3

4t

=

3

4

or

θ=tan

−1

(

3

4

)=53

∘

Answer 2

Answer:

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