The position of the particle is given by r = 3ti+ 2t^2j+ 5k where t is measured in seconds and
r in meters. Find v(t) and a(t) of the particle.
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Answer:
v(t) = 3i + 4tj
a(t) = 4j
Explanation:
dv=dr/dt
V = d/dt of 3ti+ 2t^2j + 5k
V(t) = 3i +4tj + 0k
V(t) = 3i + 4tj
a(t) = d/dt of 3i + 4tj
a(t) = 0i + 4j
a(t) = 4j
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