Question

the position of the particle is given by x=t^2-2t+5 then average velocity between first2 seconds is

Answer 1

Hey!!

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average velocity = net displacement /time

at t=0 postion of particle is 0-0+5 =5 m

at t=2 s position is =2^2-2×2+5=5

so average velocity = (5-5)/2=0 m/s

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Thanks!!