Question

the position of the particle is represent by y= ut-1/2gt2. what is the force acting on the particle?​

Answer 1

Answer:

v=ut+

2

1

×gt

2

Differentiate y with respect to t which gives velocity as dy/dt = v

dt

dv

= u+

2

1

g(2t)

v=u + gt -------------------Eqn (1)

Differentiate v with respect to t which gives velocity as d2y/dt2 = dv/dt = a

dt

dv

= 0 + g

a = g ----------------------Eqn (2)We know that force acting on a mass m is given by F = ma

Now from Eqn (2), substitute a =g, Hence, F = mg

hope it helps you

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