Question

the position of the particle is x = (2t^2 + 2 +1)m and y = ( t^2+3t +2) m Find the initial velocity​

Answer 1

Answer:

Correct option is

A

53∘ with x-axis

Given: r=3ti^+2t2j^+5k^

Velocity, v=dtdr=dtd(3ti^+2t2j^+5k^)

                              =3i^+4tj^ ms−1

Let θ be the angle in which the direction of v makes with the x-axis. 

At t=1sec:

Then tanθ = vxvy=34t=34 or 

θ=tan−1(34)=53∘

Explanation:

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