Question

The position of the particle moving in a straight line is given by x=2-5t +6tsquares find the acceleration of the particle at t=2second​

Answer 1

Answer:

Acceleration of the particle is 12 m/s²

Explanation:

Particle is moving along straight line , x = 6t²-5t+2     ---------(1)

To find velocity , differentiate equation (1)

v = dx/dt = d(6t²-5t+2)/dt

v = 12t-5

To find acceleration, differentiate equation (1) again,

a = dv/dt = d(12t-5)/dt

a = 12 m/s²

Therefore, the acceleration of the particle is 12 m/s²