Question

the position of x of an object as function of time is x = 2 + 3t ( where x is in metre and t in second) the acceleration of the object at t = 2s will be​

Answer 1

Answer:

0

Explanation:

We have

displacement given by,

x= 2+3t

Velocity after differentiating the terms will be,

$\frac{dx}{dt} = \frac{d(2+3t)}{dt}= 3m/s$

The acceleration after differentiating the terms of velocity  will be

$\frac{dv}{dt} = \frac{d(3)}{dt} = 0$

As you can see regardless of what the time period is the rate of change of velocity is 0 i.e there is no acceleration in the body.  

So even if it's t= 2s (or can be any other point) will be 0.