Question

The position time equation of a particle is x=at^2+2b where a=2 and b=3, find the velocity at t=3 sec

Answer 1

here ur answer........

Answer 2

hey mate,
I tried to answer you
please see
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eq. of position vs time is
$x = a {t}^{2} + 2b$
here, a = 2 & b = 3
so,
$x =( 2) {t}^{2} + 2(3)$

$= > \frac{dx}{dt} = \frac{d}{dt} (2 {t}^{2} + 6)$

$\frac{dx}{dt} = v$

$v = 4t$
NOW,
velocity at t = 3 sec ,
$v = (3)\times4 (\frac{m}{sec} )$
v = 12 m/sec

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please mark as brainlist

TH@NkS