Question

The position time equation of body in one dimension is x= 3t^2 - 8t + 2
Find acceleration - equation for acceleration is, a= dv/dt
please answer this question with explanation ​

Answer 1

Answer:

dt

dv

=6−3v

dv=(6−3v)dt

∫

6−3v

dv

=∫dt

3

−1

ln(6−3v)=t+lnc

c

6−3v

=e

−3t

6−3v=ce

−3t

v=

3

1

(6−ce

−3t

)

at t=0,v=0

c=6

from above eqation

v=2(1−e

−3t

)

Step-by-step explanation:

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