Question

The position time graph of a particle of mass 0.1 kg is given. The impulse at time is​

Answer 1

Explanation:

Velocity between t=0 and t=2 sec ⟹vi= dx dt = 4 2 =2m/s  Velocity at t=2 sec, vf =0  Impulse = Change in momentum =m(vf−vi) =0.1(0-2) = -0.2 kg m sec−1