Question

The position-time (x-t) graphs for two children A and B returning from their school O to their homes P and Q respectively are shown in the figure. Choose the correct entries in the brackets below:
a. (A/B) lives closer to the school than (B/A)
b. (A/B) starts from the school earlier than (B/A)
c. (A/B) works faster than (B/A)
d. A and B reach home at the (same/different) time.
e. (A/B) overtakes (B/A) on the road (once/twice).

Answer 1

Hii dear,

# Answers-
Analysing the postion-time graph carefully we can say that,
(a) A lives closer to school than B.
(b) A starts from school earlier than B.
(c) B walks faster than A.
(d) A and B reach home at the same time.
(e) B overtakes A once on the road.

Hope that is helpful. Keep asking.

Answer 2

After interpreting the graph , we can say that :

a) As OP < OQ.

So A lives closer to school than B

b)  X=0 , t=0 for A; where as t has some value for B

Therefore A starts from the school earlier than B

C) Since the velocity is equal to slope of X-t graph in case of uniform motion and slope of X-t graph of B is greater than A

Hence B walks faster than A

d) Both A and B reach the home at the same time … as corresponding to points P and Q the value of t at X-t graph of A and B is same.

e) The x-t graph for A and B intersect each other only once. Since B starts from the school afterwards therefore B overtakes A on the road once.