Question

the position vactor of a particle is given by r vactor=(2ticap+5t^2jcap)m then the angle between initial velocity and initial acceleration is​

Answer 1

Answer:

Explanation:

=(t  

2

−4t+6)  

i

^

+(t  

2

)  

j

^

​  

 

velocity =  

dt

dr

​  

=(2t−4)  

i

^

+(2t)  

j

^

​  

 

acceleration =  

dt

dv

​  

=(2)  

i

^

+(2)  

j

^

​  

 

a

.  

v

=((2t−4)  

i

^

+(2t)  

j

^

​  

).((2)  

i

^

+(2)  

j

^

​  

)

when they are perpendicular then a.v = 0  

((2t−4)  

i

^

+(2t)  

j

^

​  

).((2)  

i

^

+(2)  

j

^

​  

)=0

(2t−4)×2+4t=0

4t−8+4t=0

t=1s