The position vector of a moving particle at time t after the start of motion is given by
T= (5+ 20 t)i + (95+ 10t-5t^2)j Find its initial velocity. At time t= T the partide is moving at night
angles to its initial direction of motion. Find T, and the distance of the particle from its initial position
at this time.
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the first vector of a moving particle at time after I started motion by given equal to 5 23 + 5 find the scope find karna hai aapane method angle of emotion and the distance
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