Question

the position vector of a particle in motion is given in s.i unit in the form of function of time as follows r=3t2i+6t3j+t4k​

Answer 1

Answer:

r(i)=Initial position vector

r(f)=Final position vector

Since r is the fiction to time.

r(i)=r(0)=7

k

r(f)=r(0)=3×10

2

i

+4×(10)

2

j

+7

k

Now,

Displacement vector =r(f)−r(i)

D=

∣

∣

∣

∣

300

i

+400

j

+(7−7)

k

∣

∣

∣

∣

=

300

2

+400

2

=500