Question

The position vector of a particle is given as
1 = (t²- 4t+6) î + (t²) jcap. The time after which the
velocity vector and acceleration vector becomes
perpendicular to each other is equal to :-
(1) 1 sec. (2) 2 sec. (3) 1.5 sec. (4) 5 sec.​

Answer 1

2 sec should be the answer.....

for method see 3 images..

I hope you got your answer.......

If any mistake than sorry for it...