The position vector of an object at any time t is given by 3t2i + 6t j+k. Its velocity along y-axis has the
magnitude
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Hi dude....
HERE IS UR ANSWER:
X = 3t² i + 6t j + 1.k
differentiate with respect to time
dx/dt = 6t i + 6j + 0k
we know , dx/dt = velocity
so,
v = 6t i + 6 j + 0.k
hence , velocity along x -axis = 6t
velocity along y-axis = 6
and velocity along z-axis = 0
hence, velocity along y -axis = 6 unit
HOPE THIS HELPS....
@HARSHA... ✌
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