The position vector of particle changes from 10 m
east to 10 m north in one second. What is the average
velocity of the particle?
Answers
Answered by
35
Answer:
10√2 m/s
Explanation:
Initial position of the particle is 10 m east.
so if x is taken as the position then x₁ = 10i
final postion is 10 m north.
so x₂ = 10j
total displacement wil be x₂ - x₁ = 10j - 10i
so magnitude of total displacement = √(10²+10²) [whole root of 10²+10²]
=√200
= 10√2 m
Average velocity = total displacement ÷ total time
= 10√2 ÷ 1 [ here time is given as 1 second]
= 10√2 m/s
Answered by
0
Answer:
10√2 m/s
Explanation:
√10 square +10 square
√200
10√2.
average velocity =. 10√2 / 1
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