Question

The position vector of particle is given is given by r=(2i+3j+4k)m.the magnitude of position vector will be

Answer 1

Answer:5.38m

Explanation:

Magnitude=√(2²+3²+4²)

=√4+9+16

=√29

=5.38m

Answer 2

Answer:

Hence the answer is √29 or 5.38m

Explanation:

As per the given questions

r = (2i+3j+4k)

To find r vector: (2i+3j+4k)

To find magnitude:

|r|= √{ ( 2²) + (3²) + (4²)

 = √ ( 4+ 9+ 16)

= √29

Hence the answer is 5.38m

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