the position vector of two points A & B are 3i+j+2k and i-2j-4k respectively. Find the vector equation of the plane passing through B and perpendicular to the vector AB.
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point A (3i + j + 2k) ,point B (i - 2j - 4k)
vector AB = point B - point A
= -2i - 3j - 6k
equation of a plane passing through a point and perpendicular to a vector is
n dot r = n dot r.
(-2i - 3j - 6k) dot (xi + yj + zk) = (-2i - 3j - 6k) dot (i - 2j - 4k)
2x + 3y + 6z = 2 - 6 - 24
2x + 3y + 6z = -28
vector AB = point B - point A
= -2i - 3j - 6k
equation of a plane passing through a point and perpendicular to a vector is
n dot r = n dot r.
(-2i - 3j - 6k) dot (xi + yj + zk) = (-2i - 3j - 6k) dot (i - 2j - 4k)
2x + 3y + 6z = 2 - 6 - 24
2x + 3y + 6z = -28
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