Question

The position vectors of a point r=xi+yj+zk which mathematical relation is correct

Answer 1

Explanation:

r

=x

i

^

+y

j

^

+z

k

^

u

=

i

^

+

j

^

+

k

^

r

⋅

u

=10

(x

i

^

+y

j

^

+z

k

^

)⋅(

i

^

+

j

^

+

k

^

)=10

x+y+z=10

HERE x,y,z are natural number So x,y,z cannot be negative and zero as well

so atleast x,y,z should be 1

so values of x,y,z vary from 2 to 8

So combination of values becomes (

3

7

)+1

possible values=

4!3!

7!

+1

possible values=

3×2×1

7×6×5

+1

possible values=35+1

possible values=36