The position vectors of a point r=xi+yj+zk which mathematical relation is correct
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Explanation:
r
=x
i
^
+y
j
^
+z
k
^
u
=
i
^
+
j
^
+
k
^
r
⋅
u
=10
(x
i
^
+y
j
^
+z
k
^
)⋅(
i
^
+
j
^
+
k
^
)=10
x+y+z=10
HERE x,y,z are natural number So x,y,z cannot be negative and zero as well
so atleast x,y,z should be 1
so values of x,y,z vary from 2 to 8
So combination of values becomes (
3
7
)+1
possible values=
4!3!
7!
+1
possible values=
3×2×1
7×6×5
+1
possible values=35+1
possible values=36
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