Question

the position vectors of point P and Q are given by vector r1=2i+3j-k, vector r2=4i-3j+2k. determine PQ vector in term of rectangular unit vector i,j,k and find its magnitude.

Answer 1

Answer:

PQ = 2i - 6j + 3k

|PQ| = 7 units

Explanation:

r1 = 2i+3j-k

r2 = 4i-3j+2k

ΔPQ = r2 - r1

==>  2i - 6j + 3k

Now, $|PQ| = \sqrt{2^{2}+(-6)^{2}+(3)^{2} }$

So,

$|PQ| = \sqrt{4+36+9 }$

Therefore,

$|PQ| = \sqrt{49}$

|PQ| = 7 units

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