Physics, asked by vinaylumbardarkumar5, 1 month ago

The position (x) of a particle at time t, is given by equation x(t) a -6 (1-eme), where Vo is a constant and a > 0. The dimensions of Vo and a may be respectively OPTIONS CLEAR RESPONSE MARK FOR REVIEW OA) (LT-11, (T) B) (L-T-'1. (T-' C) (L-T), (T-1) D) (LT), (T)​

Answers

Answered by AngelicSparks29
0

Answer:

Here your answer⤵️

Explanation:

x(t)=( αV0)(1−C −αt )V0

is constant and α>0

Since, C is constant so αt should be unitless

So unit α=sec

−1 =[T −1 ]x is length, x is in metre.

V0 =xαV0 =Msec −1V/ 0 =[LT −1 ]α=[T −1 ]

The position of a particle at time t is given by the relation x(t)=(αv0)(1−c−αt), where v0 is a constant and α>0.

Hope its help..⤴️

Answered by gaurianushka987
0

Refer to the attachment

hope it will help you a lot

Attachments:
Similar questions