Question

The position ‘x’ of a particle changes with time as x= 3t2 -2t+4 . Find velocity at t=2s​

Answer 1

Answer:

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Explanation:

Solution

x = t³ + 3t² + 2t ⇒ v = dx dt

3t² + 6t+2

dv dt ⇒a= - = 6t + 6