The position (x) of a particle depends on its velocity(v) and time(t) as given by the relation x=Pv+Q/P+t. Find the dimensions of PQ.
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Answered by
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By principle of homogeneity,
Dimension of T = Dimension of Pv
[ T] = [ P] * [ LT^-2]
[ T] / [ LT ^-2] = P
[L^-1 T ^3] = P
Dimension of T = Dimension of Q/P
[ T] = [ Q] / [ L^-1 T ^3]
[ T] *[ L^-1 T ^3] = Q
[ L^-1 T ^4] = Q
Dimension of T = Dimension of Pv
[ T] = [ P] * [ LT^-2]
[ T] / [ LT ^-2] = P
[L^-1 T ^3] = P
Dimension of T = Dimension of Q/P
[ T] = [ Q] / [ L^-1 T ^3]
[ T] *[ L^-1 T ^3] = Q
[ L^-1 T ^4] = Q
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Answer:
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Hope this helps!
@Shailene
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