The position x of a particle moving along a straight line path varies with time according to the relation x=6t square -5t,where x is in metre,t is in second. The initial velocity of the particle is
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The position of particle moving along a straight line path varies with time according to the relation x = 6t² - 5t , where x is in metre and t is in second.
x = 6t² - 5t
differentiate x with respect to t,
dx/dt = 12t - 5
we know, velocity is the rate of change of displacement.
so, dx/dt = v(t)
e.g., v(t) = 12t - 5
at t = 0 , v(t = 0) = -5
hence, initial velocity of particle is - 5m/s [ here negative sign indicates direction of velocity is just opposite to its motion. ]
x = 6t² - 5t
differentiate x with respect to t,
dx/dt = 12t - 5
we know, velocity is the rate of change of displacement.
so, dx/dt = v(t)
e.g., v(t) = 12t - 5
at t = 0 , v(t = 0) = -5
hence, initial velocity of particle is - 5m/s [ here negative sign indicates direction of velocity is just opposite to its motion. ]
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Answer:
The position of particle moving along a straight line path varies with time according to the relation x = 6t² - 5t , where x is in metre and t is in second.
x = 6t² - 5t
differentiate x with respect to t,
dx/dt = 12t - 5
we know, velocity is the rate of change of displacement.
so, dx/dt = v(t)
e.g., v(t) = 12t - 5
at t = 0 , v(t = 0) = -5
hence, initial velocity of particle is - 5m/s
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