Physics, asked by donachatterjee, 1 month ago

The position (x) of a particle moving along the x-axis varies with time () as shown in the figure. The average acceleration of particle in time interval t = 0 to 8 seconds is
plz solve and reply. ​

Answers

Answered by ayubpasha5786
0

Answer:

Answer

Correct option is

B

-5 m/s

2

average acceleration a=

t

v

2

−v

1

eq(1)..

intial velocity is the slop of the graph in between the 0 to 2sec

v

1

=

2

40

=20ms

−1

final velocity os the slop of the graph in between the 6-8sec

v

2

=−

2

40

=−20ms

−1

total time is 8sec.

put v_{1}and v_{2} in eq(1)

a=

8

−20−20

=

8

−40

=−5ms

−2

Hence the answer is B option.

Answered by saivarshiniseelam
1

Answer:

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Explanation:

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