Question

The position x of a particle varies with time t as x=at

Answer 1

Answer:

Position x of a particle varies with time as

x = at

Differentiating both sides wrt t,

we get,

$= > \frac{dx}{dt} = \frac{d}{dt} (at) \\ \\ = > \frac{dx}{dt} = a \frac{dt}{dt} \\ \\ = > \frac{dx}{dt} = a$

But,

$\frac{dx}{dt} = v \: \: (velocity)$

Therefore,

$= > v = a$

Here,

Velocity is constant.

Therefore,

acceleration is zero.