The position x of a particle varies with time t as x=at? - bt', where a and b are constant. What will be the velocity of ground with respect to particle at t=ls? (1)
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The position x of a particle varies with time t as x=at^(2)-bt^(3). The acceleration at time t of the particle will be equal to zero, where (t) is equal to . Asseleatin will be zero if 2a-6bt=0⇒t=2a6b=a3b.
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