The position x of a particle varies with time t as :
x=at2 + bt3
At what time acceleration of the particle will be zero?
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The position x of a particle varies with time t as x=at2-bt3. The acceleration at time t of the particle will be equal to zero, where (t) is equal to . ` Asseleatin will be zero if 2a-6bt=0⇒t=2a6b=a3b.
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Answered by
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Answer:
Distance (x) = at2 − bt3.
Therefore velocity (v) = dx/dt
= d/dt (at2 − bt3)
=2at−3bt2
and acceleration = dv/dt
= d/dt (2at − 3bt2)
= 2a − 6bt
= 0
or t = 2a/6b
=a/3b.
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