Question

the position x of a particle with respect to time 't' along x axis is given by : x= 4t^2 - t^3 where x is in meteres and t is in seconds . what will be the maximum speed along the 4 + x direction.





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Answer 1

Explanation:

ANSWER

Given that,

x=9t

2

−t

3

.....(I)

We know that,

v=

dt

dx

The maximum speed is

v=18t−3t

2

v maximum, at

dt

dv

=0

dt

dv

=18−6t

The time will be

0=18−6t

t=3 sec

The position of the particle at 3 sec

Put the value of t in equation (I)

x=9×9−27

x=81−27

x=54 m

The position of the particle will be 54 m.