Question

The position x of an object as function of time / IS,
x = 2+3t (where x is in metre and t is in second)
The acceleration of the object at t=2s will be​

Answer 1

Explanation:

x = 2+3t

x=8m/s²

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Answer 2

　　　　 　 　

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↪WELCOME to the concept of differentiation defined the velocity and the acceleration

↪dy/dx gives velocity weather dy^2/dx^2 gives Acceleration

Now the funtion something odd means its should be reversed...

Finding dx^2/dy^2 = 0

Therfore dy^2/dx^2 =0

hence is acceleration is zero means constant