Physics, asked by tanishdua14, 1 month ago

The position x of an object changes with time tas x = t3-2t + 8, where x is in metre and tis in second. The net displacement of the object in time interval t = 1 s to t= 3 s IS о 44 m о 36 m d 50 m o 22 m​

Answers

Answered by ayushorabhi
0

Position x = t³ - 2t + 8

position at time t = 1 sec :  x₁ = 1³ - 2*1 + 8 = 7

position at time t = 3 sec :  x₃ = 3³ - 2*3 + 8 = 29

Displacement = change in position = Δx =  x₃ -  x₁ = 29 - 7 = 22m

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