the position (x) time(t) graph for a particle of mass 1 kg moving along x axis .find impulse on particle at t=4sec
answer is 10kgm/s
Attachments:
Answers
Answered by
102
I am answering this based on that diagram
Impulse = Pf - Pi
(where P = momentum = mv)
Pi = m(d/t) = 1(20/4) = 5 kg m/s
Pf = m(d/t) = 1(-20/4) = -5 kg m/s
I = Pf - Pi = -5 -5 = -10 kg m/s
i hope it will help youregards
Impulse = Pf - Pi
(where P = momentum = mv)
Pi = m(d/t) = 1(20/4) = 5 kg m/s
Pf = m(d/t) = 1(-20/4) = -5 kg m/s
I = Pf - Pi = -5 -5 = -10 kg m/s
i hope it will help youregards
Answered by
21
impulse = change in momentum
e.g.,
here in graph it is clear that , velocity of particle from 0 to 4 sec is positive { 20/4 = 5m/s} and velocity of particular from 4 to 8 sec is negative { -20/4 = -5 m/s}.
so,
....(i)
and
....(ii)
Impulse = -5 - 5 = -10 kgm/s [from eqs. (i), (ii)]
Similar questions