Question

the position y of a body as a function of time t is given as y=t^3-3t^2+6.the velocity of body is​

Answer 1

Answer:

y= t³-3t²+6

dy/dt= d(t³)/dt- d(3t²)/dt + d(6)/dt

we are differentiating here...

= 3t²- 6t + 0

hence, velocity = 3t²- 6t

you can obtain velocities by putting the value of 't'in the equation.

hope it helps you❤