Question

The positive integers A, B, A - B, and A + B are all prime numbers. The sum of these four primes is

(A) even
(B) divisible by 3
(C) divisible by 5
(D) divisible by 7
(E) prime

Answer 1

Answer:

option(A)

Step-by-step explanation:

A+B+(A-B)+(A+B)

=3A+B

A is a prime so A is odd

hence 3A is also odd

B is also odd

So 3A+B=odd+odd=even

option(A) is correct

Answer 2

HERE IS YOUR ANSWER MATE

The number A-B and A+B both are either even or odd.However they are also both prime.So they must be odd.Therefore one of A & B is odd and the other is even.

The number A-B and A+B both are either even or odd.However they are also both prime.So they must be odd.Therefore one of A & B is odd and the other is even.dd and the other is even.Because A is Prime between A & B .A must be odd prime .

Therefore B = 2, the

dd and the other is even.Because A is Prime between A & B .A must be odd prime .Therefore B = 2, theonly even prime . so A-2, A and A+2 are consecutive odd prime and thus must be

dd and the other is even.Because A is Prime between A & B .A must be odd prime .Therefore B = 2, theonly even prime . so A-2, A and A+2 are consecutive odd prime and thus must be3,5 , 7 .

HOPE IT HELPS YOU

THNXS