Question

The positive real root of the equation
64 x2 -1 = 0 is​

Answer 1

Answer:

1/8

Step-by-step explanation:

$64 {x}^{2} = 1$

${x }^{2} = \frac{1}{64}$

$x = ± \frac{1}{8}$

Hence the positive real root is

$\frac{1}{8}$

Answer 2

Answer:

positive root is 1/8

Step-by-step explanation:

64x^2-1=0 is your questions

we added positive 1 in both sides

then 64x^2=1

so x^2=1/64

then X=√(1/64)

so positive real root of the equation X=1/8