Math, asked by zakakareem7440, 10 months ago

The positive real root of the equation 64x2-1=0 is

Answers

Answered by vedantvispute38
6

Answer:

\frac{1}{8}

Step-by-step explanation:

64x^{2} -1=0\\64x^{2}=1\\x^{2}=\frac{1}{64} \\x=\frac{1}{8}   \\or\\x=\frac{-1}{8}

The positive real root is 1/8

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