Math, asked by abdullatif786, 2 months ago


The positive real root of x^2 -x-1 = 0
by the method of false position up to
second approximation is
*​

Answers

Answered by gopikrishnamanaidu
0

Answer:

64x^2-1=0 is your questions

we added positive 1 in both sides

then 64x^2=1

so x^2=1/64

then X=√(1/64)

so positive real root of the equation X=1/8

Step-by-step explanation:

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