Math, asked by parthc1920, 9 months ago

the positive real Root's of the eq. 64 x^2 -1 =0is

Answers

Answered by JarvisX27
1

64x^2=1

x^2=1/64

x= 1/64

x=1/8

Answered by AdityaPhadnis
1

Step-by-step explanation:

64x² -1 =0

x² = 1/64

So,

x=1/8 ... (Only positive as mentioned in question)

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